class Solution: def findMedianSortedArrays(self, A, B): m, n = len(A), len(B) if m > n: A, B, m, n = B, A, n, m if n == 0: raise ValueError
imin, imax, half_len = 0, m, (m + n + 1) / 2 while imin <= imax: i = (imin + imax) / 2 j = half_len - i if i < m and B[j-1] > A[i]: # i is too small, must increase it imin = i + 1 elif i > 0 and A[i-1] > B[j]: # i is too big, must decrease it imax = i - 1 else: # i is perfect
if i == 0: max_of_left = B[j-1] elif j == 0: max_of_left = A[i-1] else: max_of_left = max(A[i-1], B[j-1])
if (m + n) % 2 == 1: return max_of_left
if i == m: min_of_right = B[j] elif j == n: min_of_right = A[i] else: min_of_right = min(A[i], B[j])