leetcode-sort

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字数统计: 477 | 阅读时长 ≈ 2

归并

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def mergeSort(arr):
    import math
    if(len(arr)<2):
        return arr
    middle = math.floor(len(arr)/2)
    left, right = arr[0:middle], arr[middle:]
    return merge(mergeSort(left), mergeSort(right))


def merge(left,right):
    result = []
    while left and right:
        if left[0] <= right[0]:
            result.append(left.pop(0));
        else:
            result.append(right.pop(0));
    while left:
        result.append(left.pop(0));
    while right:
        result.append(right.pop(0));
    return result

快速排序

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def quickSort(arr, left=None, right=None):
    left = 0 if not isinstance(left,(int, float)) else left
    right = len(arr)-1 if not isinstance(right,(int, float)) else right
    if left < right:
        partitionIndex = partition(arr, left, right)
        quickSort(arr, left, partitionIndex-1)
        quickSort(arr, partitionIndex+1, right)
    return arr

def partition(arr, left, right):
    pivot = left
    index = pivot + 1
    i = index
    while  i <= right:
        if arr[i] < arr[pivot]:
            swap(arr, i, index)
            index += 1
        i += 1
    swap(arr,pivot,index - 1)
    return index - 1

def swap(arr, i, j):
    arr[i], arr[j] = arr[j], arr[i]

冒泡

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def bubble_sort(arr):
    length = len(arr):
    for i in range(length):
        for j in range(i+1, length):
            if arr[i] > arr[j]:
                arr[i], arr[j] = arr[j], arr[i]

    return arr


def bubble_sort(alist):
    # 结算列表的长度
    n = len(alist)
    # 外层循环控制从头走到尾的次数
    for j in range(n - 1):
        # 用一个count记录一共交换的次数，可以排除已经是排好的序列
        count = 0
        # 内层循环控制走一次的过程
        for i in range(0, n - 1 - j):
            # 如果前一个元素大于后一个元素，则交换两个元素（升序）
            if alist[i] > alist[i + 1]:
                # 交换元素
                alist[i], alist[i + 1] = alist[i + 1], alist[i]
                # 记录交换的次数
                count += 1
        # count == 0 代表没有交换，序列已经有序
        if 0 == count:
            break

堆排序

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def buildMaxHeap(arr):
    import math
    for i in range(math.floor(len(arr)/2),-1,-1):
        heapify(arr,i)

def heapify(arr, i):
    left = 2*i+1
    right = 2*i+2
    largest = i
    if left < arrLen and arr[left] > arr[largest]:
        largest = left
    if right < arrLen and arr[right] > arr[largest]:
        largest = right

    if largest != i:
        swap(arr, i, largest)
        heapify(arr, largest)

def swap(arr, i, j):
    arr[i], arr[j] = arr[j], arr[i]

def heapSort(arr):
    global arrLen
    arrLen = len(arr)
    buildMaxHeap(arr)
    for i in range(len(arr)-1,0,-1):
        swap(arr,0,i)
        arrLen -=1
        heapify(arr, 0)
    return arr