python回文数 发表于 2019-05-13 | 阅读次数: 字数统计: 63 | 阅读时长 ≈ 1 123str_x = str(x)return str_x == str_x[::-1] 1234567str_x = str(x)for i in range(0,int(len(str_x)/2)): if str_x[i] != str_x[-i-1]: return Falsereturn True 12345678910if x<0: return Falsetemp_x = x;palindromeNum = 0while temp_x != 0: palindromeNum = palindromeNum*10 + temp_x%10 temp_x /= 10return palindromeNum == x 1234567str_x = str(x)str_y = ""for i in str_x: str_y = i + str_yreturn str_y == str_x